indefinite integral of ln x 2 x

Evaluate: indefinite integral 1+x/1+x^2 dx? - Yahoo! Answers.

Integrate by parts lnx/x^4 dx between e and 1 urgent help needed.

Please help me evaluate this indefinite integral. Can't figure it.

Jan 28, 2013. Evaluate the definite integral. $$int_3^7. @AndréNicolas he said "It should be $ln(x^{43})$" – CBenni Jan 28 at 17:29. 3,034223.
Remember that this is a definite integral, so we must evaluate at the bounds. (1/4) x^4 [ ln(x) - (1/4) ] {evaluated from 1 to 2e} [ (1/4)[2e]^4 (ln(2e).
How do I solve the following differential equation given f of x and g of x x times f double prime over f. The second integral of 2x is the first integral of x 2 + C.
. of (ln(x)^7)/x dx? 2 years ago; Report Abuse. Let u = ln(x). Then, du/dx = 1/x du = dx/x [Rearrange the terms to make dx/x the subject] So: ∫ u^7 (dx/x).
(ln(x))^6 / x dx. Evaluate the indefinite integral. cos x / 4sin(x) + 8 dx. Evaluate the indefinite integral. 3x - 3 / (3x^2 - 6x + 7)^5 dx. 3 years ago.

indefinite integral of ln x 2 x

Evaluate the indefinite integral. 10 pts? - Yahoo! Answers.

indefinite integral of ln x 2 x

Definite integral of ln(x) ? - Yahoo! Answers.
1) Compute the indefinite integral:integral 2x ln(x2 - 8x + 18) dx 2) Note that x4 + 1 = (x4 + 2x2 +1) = (x2 + 1)2 - (√2x)2.use this trick to compute the following.
∫ {[ln (x²)] /x} dx = let x² = u → x = √u → dx = [1/(2√u)] du → ∫ {[ln (x²)] /x} dx = ∫ [(ln u) /√u][1/(2√u)] du = (1/2) ∫ [(ln u) /(√u√u)] du = (1/2) ∫ [(ln.
$from x= 0 to x=1 So I know the integral of ln(x) …. This is actually an improper integral because taking f(x) = ln(x) from x=0 to 1. lim(x-->0) -2x.$
Find the indefinite integral of: (x^4 + x - 4)/(x^2 + 2)? - Yahoo.
1) Compute the indefinite integral:integral 2x ln(x2 - 8x + 18) dx 2) Note that x4 + 1 = (x4 + 2x2 +1) = (x2 + 1)2 - (√2x)2.use this trick to compute the following.
∫ {[ln (x²)] /x} dx = let x² = u → x = √u → dx = [1/(2√u)] du → ∫ {[ln (x²)] /x} dx = ∫ [(ln u) /√u][1/(2√u)] du = (1/2) ∫ [(ln u) /(√u√u)] du = (1/2) ∫ [(ln.
$from x= 0 to x=1 So I know the integral of ln(x) …. This is actually an improper integral because taking f(x) = ln(x) from x=0 to 1. lim(x-->0) -2x.$
Indefinite integrals. Christina. Answered by Anonymous 2 minutes later. int u , dv=uv-int v , du. u = ln(x) Rightarrow du = frac{dx} dv = dx Rightarrow v = x.
Integrate by parts lnx/x^4 dx between e and 1.. 100 Votes. 2 people rated this as good. First let us calculate indefinite integral.
What is the indefinite integral of [9/(xln(4x))]dx.? So ∫[9/(x ln(4x))] dx =9 ∫[ u' * (1/u)] dx. What are the possible values for x if x^2 + 5x =6?
The only difference is that the expression in the ln parentheses is under a radical, so that it says 1/3 x^3 -2x + 1/2 ln(sqrt(x^2 + 2)) + C. Can.
What is the indefinite integral of [9/(xln(4x))]dx.? - Yahoo! Answers.